c++ - Fundamental typedef operand syntax -

given:

typedef type-declaration synonym;

i can see how:

typedef long unsigned int size_t;

declares size_t synonym long unsigned int, (know but) can't see exactly how:

typedef int (*f)(size_t, size_t);

declares f synonym pointer function (size_t, size_t) returning int

typedef's 2 operands (type-declaration, synonym) in first illustration long unsigned int , size_t.

what 2 arguments typedef in declaration of f or there perhaps overloaded versions of typedef?

if there relevant distinction between c , c++ please elaborate otherwise i'm interested in c++ if helps.

type declarations using typedef same corresponding variable declarations, typedef prepended. so,

int x; // declares variable named 'x' of type 'int' typedef int x; // declares type named 'x' 'int'

it's same function pointer types:

        int(*f)(size_t); // declares variable named f of type 'int(*)(size_t)' typedef int(*f)(size_t); // declares type named 'f' 'int(*)(size_t)'

it's not "special case;" that's function pointer type looks like.

c++ c typedef

Five