How to match a regex in python, either completely or partially -

How to match a regex in python, either completely or partially -

this basic question i've searched bit , still having doubts.

let's take next regex example:

regex_example = re.compile('\d{10}\s\d-\d{3}-\d{3}-\d{4}')

now let's imagine there string may contain substrings matching total length of regex, such '1234567890 1-123-456-7890' or may contain substrings match first part of regex, illustration '1234567890 1-123'.

i modify regex (or utilize solution) allowing me match substring has 14 or more char , matches regex either partially or entirely. code find:

'1234567890 1-1' (has 14 characters , matches start of regex) or '1234567890 1-13' or '1234567890 1-134'

and forth, total length of regex.

you can create part after first 14 characters optional:

regex_example = re.compile( '(\d{10}\s\d-\d(?:\d{0,2}(?:(?:-\d{0,3})?(?:-\d{0,4})?)?)?)')

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python regex